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char *char_ptr = "example";
int *int_ptr;

int *voidPtr2intPtr(void *v_pointer){
  return v_pointer;
}
int_ptr= voidPtr2intPtr(pointerchar_ptr);

Pointer might be aligned on even boundary, once it is cast to an int some architectures will require it to be on 4 byte boundaries. Pointers are often cast because a void* cannot be dereferenced. Careless coding can result in an arbitrary pointer type being used irregardless of its alignment.

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References

• Wiki Markup
  Bryant, Randal and O'Hallaron, David. \[ 2003 \] 2001 Computer Systems: A Programmer's Perspective. Prentice Hall. ISBN 0-13-034074-X.

• http://www.open-std.org/jtc1/sc22/wg14/www/C99RationaleV5.10.pdf