These two lines of code assume that gets() will not read more than BUFSIZ characters from stdin.  This is an invalid assumption and the resulting operation can result in a buffer overflow.
| char buf[BUFSIZ + 1]; gets(buf); | 
The standard function strncpy() and strncat() do not guarantee that the resulting string is null terminated.  If there is no null character in the first n characters of the source array pointed the result is not be null-terminated as in the following example:
| char a[16]; strncpy(a, "0123456789abcdef", sizeof(a)); | 
The correct solution depends on the original intent.  If your intent was to truncate a string but ensure that the
result was a null-terminated string the following solution can be used.
| char a[16]; strncpy(a, "0123456789abcdef", sizeof(a)-1); a[sizeof(a)] = '\0'; | 
Example using strcpy()
Example using strncpy_s()
An exception to this rule applies if the intent of the programmer was to convert a null-terminated byte string to a character array. To be compliant with this standard, this intent must be made clear statement in comments.