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The C99 standard rules define how C compilers handle conversions. These rules include integer promotions, integer conversion rank, and the usual arithmetic conversions.
Integer Promotions
Integer types smaller than int
are promoted when an operation is performed on them. If all values of the original type can be represented as an int
, the value of the smaller type is converted to an int
; otherwise, it is converted to an unsigned int
.
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Integer promotions have a number of interesting consequences. For example, adding two small integer types always results in a value of type signed int
or unsigned int
, and the actual operation takes place in this type. Also, applying the bitwise negation operator ~ to an unsigned char
(on IA-32) results in a negative value of type signed int
because the value is zero-extended to 32 bits.
Integer Conversion Rank
Every integer type has an integer conversion rank that determines how conversions are performed. The following rules for determining integer conversion rank are defined in C99.
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The integer conversion rank is used in the usual arithmetic conversions to determine what conversions need to take place to support an operation on mixed integer types.
Usual Arithmetic Conversions
The usual arithmetic conversions are a set of rules that provides a mechanism to yield a common type when both operands of a binary operator are balanced to a common type or the second and third arguments of the conditional operator ( ? : ) are balanced to a common type. Balancing conversions involve two operands of different types, and one or both operands may be converted. Many operators that accept arithmetic operands perform conversions using the usual arithmetic conversions. After integer promotions are performed on both operands, the following rules are applied to the promoted operands.
- If both operands have the same type, no further conversion is needed.
- If both operands are of the same integer type (signed or unsigned), the operand with the type of lesser integer conversion rank is converted to the type of the operand with greater rank.
- If the operand that has unsigned integer type has rank greater than or equal to the rank of the type of the other operand, the operand with signed integer type is converted to the type of the operand with unsigned integer type.
- If the type of the operand with signed integer type can represent all of the values of the type of the operand with unsigned integer type, the operand with unsigned integer type is converted to the type of the operand with signed integer type.
- Otherwise, both operands are converted to the unsigned integer type corresponding to the type of the operand with signed integer type. Specific operations can add to or modify the semantics of the usual arithmetic operations.
Example
In the following example, assume the following code is compiled and executed on IA-32:
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Assuming that the precision of signed char
is 7 bits and the precision of unsigned char
is 8 bits, this operation is perfectly safe. However, if the compiler represents the signed char
and unsigned char
types using 31 and 32 bit precision (respectively), the variable uc
would need be converted to unsigned int
instead of signed int
. As a result of the usual arithmetic conversions, the signed int
is converted to unsigned and the addition takes place between the two unsigned int
values. Also, because uc
is equal to UCHAR_MAX
, which is equal to UINT_MAX
in this example, the addition will result in an overflow. The resulting value is then zero-extended to fit into the 64-bit storage allocated by sll
.
Consequences
Misunderstanding integer conversion rules can lead to integer errors, which in turn can lead to exploitable vulnerabilites.
References
- Seacord 05 Chapter 5 Integers
- ISO/IEC 9899-1999 6.3 Conversions