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The result of the / operator is the quotient from the division of the first arithmetic operand by the second arithmetic operand. Division operations are susceptible to divide-by-zero errors. Overflow can also occur during two's-complement signed integer division when the dividend is equal to the minimum (negative) value for the signed integer type and the divisor is equal to —1. See −1 (see rule NUM00-J. Detect or prevent integer overflow for more information). This noncompliant code example can result in a divide-by-zero error during the division of the signed operands num1 and num2.:This
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long num1, num2, result; /* Initialize num1 and num2 */ result = num1 / num2; |
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This compliant solution tests the divisor to guarantee there is no possibility of divide-by-zero errors.:
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long num1, num2, result;
/* Initialize num1 and num2 */
if (num2 == 0) {
// handleHandle error
} else {
result = num1 / num2;
}
|
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The % operator provides the remainder when two operands of integer type are divided. This noncompliant code example can result in a divide-by-zero error during the remainder operation on the signed operands num1 and num2.:
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long num1, num2, result; /* Initialize num1 and num2 */ result = num1 % num2; |
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This compliant solution tests the divisor to guarantee there is no possibility of a divide-by-zero error.:
| Code Block | ||
|---|---|---|
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long num1, num2, result;
/* Initialize num1 and num2 */
if (num2 == 0) {
// handleHandle error
} else {
result = num1 % num2;
}
|
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A division or remainder by zero can result in abnormal program termination and denial-of-service (DoS).
Rule | Severity | Likelihood | Remediation Cost | Priority | Level |
|---|---|---|---|---|---|
NUM02-J | lowLow | likelyLikely | mediumMedium | P6 | L2 |
Automated Detection
Tool | Version | Checker | Description |
|---|---|---|---|
| Coverity | 7.5 | DIVIDE_BY_ZERO | Implemented |
Related Guidelines
Bibliography
Section Subclause 6.5.5, "Multiplicative Operators" | |
Chapter 5, "Integers" | |
| [Seacord 2015] | NUM02-J. Ensure that division and modulo operations do not result in divide-by-zero errors LiveLesson |
Chapter 2, "Basics" |
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