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If an integer operator other than a shift operator has at least one operand of type long, then the operation is carried out using 64-bit precision, and the result of the numerical operator is of type long. If the other operand is not long, it is first widened (§5.1.5) to type long by numeric promotion (§5.6). Otherwise, the operation is carried out using 32-bit precision, and the result of the numerical operator is of type int. If either operand is not an int, it is first widened to type int by numeric promotion.

Promotion Rules

The JLS Section 5.6 "Numeric Promotions" describes numeric promotion as the following:

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These conversions can happen with the following operators: multiplicative operators (%, *, /), additive operators (+, -), comparison operators (<, >, <=, >=), equality operators (==, !=) and the integer bitwise operators (&, |, ^).

Examples

In the following example, a is promoted to a double before the + operator is applied.

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Here, b is first converted to int so that the + operator can be applied to operands of the same type. The result of (a+b) is then converted to a float, and the comparison operator is finally applied.

Compound Operators

Sometimes invisible implicit casts occur when compound expressions are used with mixed operand types. Examples of compound assignment operators are +=, -=, *=, /=, &=, ^=, %=, <<=, >>=, >>>= and |=.

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One or more implicit invisible conversions occur when the operands are different types. When E1 is an int and E2 is either a long, a float, or a double, for example, there will be two conversions: first, a widening conversion on E1 from int to the type of E2 (before the "op"), and, second, a narrowing conversion from the type of E2 back to int (after the "op" and before the assignment).

Noncompliant Code Example (Multiplication)

In this noncompliant code example, the statement big * one carries out a binary operation. Because big is type int, and one is type float, big is promoted to the type float. This implicit cast results in loss of precision.

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This code outputs 2.0E9 whereas, the expected output is 1.999999999E9.

Compliant Solution (Multiplication)

This compliant solution uses the double type, instead of float, as a safer means of handling the widening primitive conversion resulting from integer promotion.

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This produces the expected output of 1.999999999E9. This is the value that is obtained when an int is assigned (implicitly cast) to a double.

Noncompliant Code Example (Left Shift)

This noncompliant code example shows integer promotion resulting from the use of the bit-wise OR operator. The byte array element is sign extended to 32 bits before it is used as an operand. If it originally contained the value {{0xff}}, it would contain {{0xffffffff}} \[[Findbugs 2008|AA. Bibliography#Findbugs 08]\].  

int result = 0;
for(int i = 0; i < 4; i++) 
  result = ((result << 8) | b[i]);

Compliant Solution (Left Shift)

This compliant solution continues to use integer promotion, but it masks off the upper 24 bits of the byte array element to achieve the intended result.

int result = 0;
for(int i = 0; i < 4; i++) 
  result = ((result << 8) | (b[i] & 0xff));

Noncompliant Code Example (Compound Addition & Assignment)

This noncompliant code example performs a compound assignment operation. This operation involves an int value that contains too many significant bits to fit in the twenty-three bit mantissa of a Java float, causing the widening conversion from int to float to lose precision. The resulting value could surprise many programmers.

public class Expr {
  public static void main(String[] args) {
    int x = 2147483642; // 0x7ffffffa
    x += 1.0f; // x contains 2147483647 (0x7fffffff) after the computation
  }
}

Compliant Solution (Compound Addition & Assignment)

To be safe, avoid using any of the compound assignment operators on variables of types byte, short or char. Also, refrain from using a wider operand on the right hand side. In this compliant solution, all operands are of the Java type double.

public class Expr {
  public static void main(String[] args) {
    double x = 2147483642; // 0x7ffffffa
    x += 1.0; // x contains 2147483643.0 (0x7ffffffb.0) as expected
  }
}

Noncompliant Code Example (Compound Bit Shift & Assignment)

This noncompliant code example uses a compound right shift operator for shifting the value of i, bit by bit. Unfortunately, the value of i remains the same. The value of i is first promoted to an int. This is a widening primitive conversion, so no data is lost. With short, -1 is represented as 0xffff. The conversion to int results in the value 0xffffffff, which is right shifted by 1 bit to yield 0x7fffffff. To store the value back into the short variable i, Java then performs an implicit narrowing conversion, discarding the 16 higher order bits. The final result is again 0xffff or -1.

short i = -1;
i >>>= 1;

Compliant Solution (Compound Bit Shift & Assignment)

This compliant solution applies the compound assignment operator to an int which does not require widening and subsequent narrowing.

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