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C++ does not allow you to change the value of a reference type, effectively treating all references as being const qualified. The C++ Standard, [dcl.ref], paragraph 1 [ISO/IEC 14882-2014], states the following:

Cv-qualified references are ill-formed except when the cv-qualifiers are introduced through the use of a typedef-name (7.1.3, 14.1) or decltype-specifier (7.1.6.2), in which case the cv-qualifiers are ignored.

Thus, C++ prohibits or ignores the cv-qualification of a reference type. Only a value of non-reference type may be cv-qualified.

When attempting to const-qualify a value of type as part of a declaration that uses reference type, a programmer may accidentally write

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In this noncompliant code example, a const-qualified reference to a char is formed instead of a reference to a const-qualified char is formed, resulting . This results in undefined behavior:.

#include <iostream>
 
void f(char c) {
  char &const p = c;
  p = 'p';
  std::cout << c << std::endl;
}

Implementation Details (MSVC)

With Microsoft Visual Studio 2015, this code compiles successfully with a warning diagnostic (.

warning C4227: anachronism used : qualifiers on reference are ignored

When run, the code outputs the following. ignored) and outputs

p

Implementation Details (Clang)

With Clang 3.9, this code produces a fatal diagnostic:.

error: 'const' qualifier may not be applied to a reference

Compliant Solution

Noncompliant Code Example

This noncompliant code example correctly declares p to be a reference to a const-qualified char. The subsequent modification of p makes the program ill-formed.This compliant solution assumes the programmer intended for the previous example to fail to compile due to attempting to modify a const-qualified char reference:

#include <iostream>
  
void f(char c) {
  const char &p = c;
  p = 'p'; // Error: read-only variable is not assignable
  std::cout << c << std::endl;
}

Compliant Solution

This compliant solution removes the const qualifier.

#include <iostream>
 
void f(char c) {
  char &p = c;
  p = 'p';
  std::cout << c << std::endl;
}

Risk Assessment

A const and  or volatile reference types type may result in undefined behavior instead of a fatal diagnostic, causing unexpected values to be stored and leading to possible data integrity violations.

Automated Detection

Related Vulnerabilities

Search for vulnerabilities resulting from the violation of this rule on the CERT website.

Bibliography

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