You are viewing an old version of this page. View the current version.

Compare with Current View Page History

« Previous Version 37 Next »

An object deriving from a base class typically contains additional member variables that extend the base class. When by-value assigning or copying an object of the derived type to an object of the base type, those additional member variables are not copied because there is insufficient space within the base class in which to store them. This act is commonly referred to as slicing the object as the additional members are "sliced off" the resulting object.

Do not initialize an object of base class type with an object of derived class type, except through references, pointers, or pointer-like abstractions (such as std::unique_ptr, or std::shared_ptr).

Noncompliant Code Example

In this noncompliant code example, an object of the derived Manager type is passed by value to a function accepting a base Employee type. This results in slicing the Manager objects, resulting in information loss and unexpected behavior when the print() function is called.

#include <iostream>
#include <string>

class Employee {
  std::string Name;
  
protected:
  virtual void print(std::ostream &OS) const {
    OS << "Employee: " << getName() << std::endl;      
  }
  
public:
  Employee(const std::string &Name) : Name(Name) {}
  const std::string &getName() const { return Name; }
  friend std::ostream &operator<<(std::ostream &OS, const Employee &E) {
    E.print(OS);
    return OS;
  }
};
 
class Manager : public Employee {
  Employee Assistant;
  
protected:
  void print(std::ostream &OS) const override {
    OS << "Manager: " << getName() << std::endl;
    OS << "Assistant: " << std::endl << "\t" << getAssistant() << std::endl;      
  }
  
public:
  Manager(const std::string &Name, const Employee &Assistant) : Employee(Name), Assistant(Assistant) {}
  const Employee &getAssistant() const { return Assistant; }
};

void f(Employee E) {
  std::cout << E;    
}

int main() {
  Employee Coder("Joe Smith");
  Employee Typist("Bill Jones");
  Manager Designer("Jane Doe", Typist);
  
  f(Coder);
  f(Typist);
  f(Designer);
}

When f() is called with the Designer argument, the formal parameter in f() is sliced and information is lost. Thus, when the Employee object is printed, Employee::Print() is called instead of Manager::Print(), resulting in the output:

Employee: Jane Doe

Compliant Solution (Pointers)

Using the same class definitions as above, this compliant solution modifies the definition of f() to require raw pointers to the object, removing the slicing problem:

void f(const Employee *E) {
  if (E) {
    std::cout << *E;
  }
}

int main() {
  Employee Coder("Joe Smith");
  Employee Typist("Bill Jones");
  Manager Designer("Jane Doe", Typist);
  
  f(&Coder);
  f(&Typist);
  f(&Designer);
}

This compliant solution also complies with EXP34-C. Do not dereference null pointers in the implementation of f(). With this definition, the output becomes:

Employee: Joe Smith
Employee: Bill Jones
Manager: Jane Doe
Assistant: 
	Employee: Bill Jones

Compliant Solution (References)

An improved compliant solution, which does not require guarding against null pointers within f(), uses references instead of pointers:

void f(const Employee &E) {
  std::cout << E;
}

int main() {
  Employee Coder("Joe Smith");
  Employee Typist("Bill Jones");
  Manager Designer("Jane Doe", Typist);
  
  f(Coder);
  f(Typist);
  f(Designer);
}

Noncompliant Code Example

This noncompliant code example uses the same class definitions of Employee and Manager from above, and attempts to store Employee objects in a std::vector. However, because std::vector requires a homogeneous list of elements, slicing occurs.

// In addition to the #includes from the previous example.
#include <vector>
 
void f(const std::vector<Employee> &V) {
  for (const auto &E : V) {
    std::cout << E;
  }
}

int main() {
  Employee Typist("Joe Smith");
  std::vector<Employee> V{Typist, Employee("Bill Jones"), Manager("Jane Doe", Typist)};
  f(V);
}

Compliant Solution

This compliant solution stores std::unique_ptr smart pointers in the std::vector, which eliminates the slicing problem:

// In addition to the #includes from the previous example.
#include <memory>
#include <vector>

void f(const std::vector<std::unique_ptr<Employee>> &V) {
  for (const auto &E : V) {
    std::cout << *E;
  }
}

int main() {
  std::vector<std::unique_ptr<Employee>> V;
  
  V.emplace_back(new Employee("Joe Smith"));
  V.emplace_back(new Employee("Bill Jones"));
  V.emplace_back(new Manager("Jane Doe", *V.front()));
  
  f(V);
}

Risk Assessment

Slicing results in information being lost, which could lead to abnormal program execution or denial of service attacks.

Rule

Severity

Likelihood

Remediation Cost

Priority

Level

OOP33-CPP

Low

Probable

Medium

P4

L3

Automated Detection

Tool

Version

Checker

Description

 PRQA QA-C++

 4.4

3072,3073

 

Related Vulnerabilities

Search for other vulnerabilities resulting from the violation of this rule on the CERT website.

Related Guidelines

Bibliography

[ISO/IEC 14882-2014]12.8, "Copying and Moving Class Objects"
[Dewhurst 02]Gotcha #38, "Slicing"
[Sutter 00]GotW #22: "Object Lifetimes - Part I" 

 

  • No labels