The following 19 specific conversions on primitive types are called the widening primitive conversions:
bytetoshort,int,long,float, ordoubleshorttoint,long,float, ordoublechartoint,long,float, ordoubleinttolong,float, ordoublelongtofloatordoublefloattodouble
Conversion from int or long to float, or long to double may lead to loss of precision (loss of least significant bits). In this case, the resulting floating-point value is a rounded version of the integer value, using IEEE 754 round-to-nearest mode. Despite this loss of precision, the JLS requires that the conversion and rounding occur silently; that is, without any runtime exception. See JLS, Section 5.1.2, "Widening Primitive Conversion" for more information.
Note that conversions from float to double can also lose information about the overall magnitude of the converted value. See guideline FLP04-J. Use the strictfp modifier for floating point calculation consistency for additional information.
Noncompliant Code Example
In this noncompliant code example, two identical large integer literals are passed as arguments to the subFloatFromInt() method. The second argument is coerced to float, cast back to int, and subtracted from a value of type int. The result is returned as a value of type int.
This method may have unexpected results because of the loss of precision. Values of type float have 23 mantissa bits, a sign bit, and an 8 bit exponent. The exponent allows type float to represent a larger range than that of type int. However, the 23-bit mantissa means that float supports exact representation only of integers whose representation fits within 23 bits; float supports only approximate representation of integers outside that range.
class WideSample {
public static int subFloatFromInt(int op1, float op2) {
return op1 - (int)op2;
}
public static void main(String[] args) {
int result = subFloatFromInt(1234567890, 1234567890);
// This prints -46, and not 0 as may be expected
System.out.println(result);
}
}
Compliant Solution (ArithmeticException)
This compliant solution range checks the argument of the integer argument (op1) to ensure it can be represented as a value of type float without a loss of precision.
class WideSample {
public static int subFloatFromInt(int op1, float op2) throws ArithmeticException {
// The significand can store at most 23 bits
if ((op1 > 0x007fffff) || (op1 < -0x800000)) {
throw new ArithmeticException("Insufficient precision");
}
return op1 - (int)op2;
}
public static void main(String[] args) {
int result = subFloatFromInt(1234567890, 1234567890);
System.out.println(result);
}
}
In this example, the subFloatFromInt() method throws java.lang.ArithmeticException.
Compliant Solution (wider type)
This compliant solution accepts an argument of type double instead of an argument of type float. Values of type double have 52 mantissa bits, a sign bit, and an 11 bit exponent. Consequently, integer values of type int and narrower can be converted to double without a loss of precision.
class WideSample {
public static int subDoubleFromInt(int op1, double op2) {
return op1 - (int)op2;
}
public static void main(String[] args) {
int result = subDoubleFromInt(1234567890, 1234567890);
// Works as expected
System.out.println(result);
}
}
Risk Assessment
Converting integer values to floating-point types whose mantissa has fewer bits than the original integer value will lose precision.
Guideline |
Severity |
Likelihood |
Remediation Cost |
Priority |
Level |
|---|---|---|---|---|---|
FLP10-J |
low |
unlikely |
medium |
P2 |
L3 |
Automated Detection
Automatic detection of casts that can lose precision is straightforward. Sound determination of whether those casts correctly reflect the intent of the programmer is infeasible in the general case. Heuristic warnings could be useful.
Related Vulnerabilities
Search for vulnerabilities resulting from the violation of this guideline on the CERT website.
Related Guidelines
C Secure Coding Standard: FLP36-C. Beware of precision loss when converting integral types to floating point
C++ Secure Coding Standard: FLP36-CPP. Beware of precision loss when converting integral types to floating point
Bibliography
[[JLS 2005]] Section 5.1.2
, "Widening Primitive Conversion"
INT02-J. Do not assume that the remainder operator always returns a non-negative result 03. Integers (INT) INT04-J. Avoid using the char integral type to hold signed values